python - numpy: is there an `allclose(np.array, scalar)`? -


in numpy can use allclose(x, y) function check element-wise approximate equality between 2 arrays. moreover, expression x==5 can check element-wise equality between array , scalar.

is there function combines both functionalities?? is, can compare array , scalar approximate element-wise equality??

the term array or array-like in numpy documentation indicates input converted array np.asarray(in_arg) or np.asanyarray(in_arg). if input scalar converted scalar array:

>>> import numpy np >>> np.asarray(5)    # or np.asanyarray array(5)

and functions np.allclose or np.isclose element-wise comparison no matter if second argument scalar array, array same shape or array correctly broadcasts first array:

>>> import numpy np >>> arr = np.array([1,2,1,0,1.00001,0.9999999]) >>> np.allclose(arr, 1) false >>> np.isclose(arr, 1) array([ true, false,  true, false,  true,  true], dtype=bool)  >>> np.isclose(arr, np.ones((10, 6))) array([[ true, false,  true, false,  true,  true],        [ true, false,  true, false,  true,  true],        [ true, false,  true, false,  true,  true],        [ true, false,  true, false,  true,  true],        [ true, false,  true, false,  true,  true],        [ true, false,  true, false,  true,  true],        [ true, false,  true, false,  true,  true],        [ true, false,  true, false,  true,  true],        [ true, false,  true, false,  true,  true],        [ true, false,  true, false,  true,  true]], dtype=bool)

so no need find function explicitly handles scalars, these functions correctly work scalars.


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