recursion - recursive itemgetter for python -

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• xpath query nested python dictionaries 7 answers

is there recursive itemgetter in python. let's have object

d = {'a': (1,2,3), 'b': {1: (5,6)}} 

and wanted first element of tuple d['a']? far can tell itemgetter 1 level, i.e. me a or b or both.

is there clever way of combining itertools itemgetter produce desired result.

so want able call

from operator import itemgetter d = {'a': (1,2), 'b': (4, (5,))} itemgetter({'a': 0})(d) --> 1 itemgetter({'b': 0})(d) --> 4 itemgetter({'b': {1: 0}})(d) --> 5  d = {'a': {'b': (1,2,3)}} itemgetter({'a': {'b': 2}})(d) --> 3 

i don't 'clever' ways. obvious better.

you can write getter iterates along list of subscripts:

def getter(x, *args):   p = x   s in args:     p = p[s]   return p  >>> d = {'a': (1,2,3), 'b': {1: (5,6)}} >>> getter( d, 'a', 0) 1