node.js - if statement get skipped in javascript -

i writing basic application value arguments , display them. have 2 files:

1. app.js

   console.log('application launching');  const fs = require('fs'); const yarg = require('yargs'); const node = require('./node.js')  var command = yarg.argv;  if (command === '3' ) {   console.log("adding note");   node.addnote(argv.name,argv.title); } else {   console.log('invalid'); } 

2. node.js

   console.log("im up")  var addnote = (name,title) => {   console.log('welcome', title, name); };  module.export = {   addnote } 

this output when pass argument:

admins-mac:node admin$ node app.js --3 tony mr

application launching

im up

invalid

if knowledge right, output must welcome mr tony.

i can't figure out error.

yargs giving object of parameters. need check

if (command[3]) {     // ... } 

however, we'd have errors here

node.addnote(argv.name,argv.title); 

as did't pass anything, , neither argv.name defined nor argv.title.

so given command:

node app.js --3 --name=tony --title=mr 

you need code:

let command = yarg.argv; if (command[3]) {     console.log("adding note");     addnote(command.name,command.title); } 

third, don't require nodejs. it's environment. instead, need require file holding second code block.

const addnote = require("./2nd.js"); 

assumed file called 2nd.js , in same folder.

---

to wrap things (there number of other errors in code) , here's working rewrite of code:

1st.js:

const fs = require('fs'); const yarg = require('yargs'); const addnote = require("./2nd.js");  let command = yarg.argv;  if (command[3]) {     console.log("adding note");     addnote(command.name, command.title);  }  else {     console.log('invalid'); } 

---

2nd.js:

let addnote = (name,title)=>{     console.log(`welcome, ${title} ${name}`); };  module.exports = addnote; 

run with

node 1st.js --3 --name=tony --title=mr