sql server - SQL Stored Procedure Combine UNION rows into 1 row -


i love know how put results of query 1 row instead of 3 rows gives back: 

select count([fms].[dbo].[booking].bookingnumber) [fms].[dbo].[booking] inner join [fms].[dbo].[container] on [fms].[dbo].[booking].[bookingnumber] = [fms].[dbo].[container].[bookingnumber] inner join [fms].[dbo].[file] on [fms].[dbo].[container].filenumber = [fms].[dbo].[file].filenumber [fms].[dbo].[booking].relationcode = 'ship02' , [fms].[dbo].[file].eta between '2000-10-27' , '2016-10-28'  union  select count([fmsair].[dbo].[booking].bookingnumber) [fmsair].[dbo].[booking] inner join [fmsair].[dbo].[container] on [fmsair].[dbo].[booking].[bookingnumber] = [fmsair].[dbo].[container].[bookingnumber] inner join [fmsair].[dbo].[file] on [fmsair].[dbo].[container].filenumber = [fmsair].[dbo].[file].filenumber [fmsair].[dbo].[booking].relationcode = 'ship02' , [fmsair].[dbo].[file].eta between '2000-10-27' , '2016-10-28'  union  select count([fmsprojects].[dbo].[booking].bookingnumber) [fmsprojects].[dbo].[booking] inner join [fmsprojects].[dbo].[container] on [fmsprojects].[dbo].[booking].[bookingnumber] = [fmsprojects].[dbo].[container].[bookingnumber] inner join [fmsprojects].[dbo].[file] on [fmsprojects].[dbo].[container].filenumber = [fmsprojects].[dbo].[file].filenumber [fmsprojects].[dbo].[booking].relationcode = 'ship02' , [fmsprojects].[dbo].[file].eta between '2000-10-27' , '2016-10-28'

is there way can combine 3 result rows , count them 1 row. using inside stored procedure.

if want sum count of 3 select queries, this:

select sum(cnt) from(    select count([fms].[dbo].[booking].bookingnumber) cnt    [fms].[dbo].[booking]    inner join [fms].[dbo].[container] on [fms].[dbo].[booking].[bookingnumber] = [fms].[dbo].[container].[bookingnumber]    inner join [fms].[dbo].[file] on [fms].[dbo].[container].filenumber = [fms].[dbo].[file].filenumber    [fms].[dbo].[booking].relationcode = 'ship02' , [fms].[dbo].[file].eta between '2000-10-27' , '2016-10-28'    union    select count([fmsair].[dbo].[booking].bookingnumber)     [fmsair].[dbo].[booking]    inner join [fmsair].[dbo].[container] on [fmsair].[dbo].[booking].[bookingnumber] = [fmsair].[dbo].[container].[bookingnumber]    inner join [fmsair].[dbo].[file] on [fmsair].[dbo].[container].filenumber = [fmsair].[dbo].[file].filenumber    [fmsair].[dbo].[booking].relationcode = 'ship02' , [fmsair].[dbo].[file].eta between '2000-10-27' , '2016-10-28'    union    select count([fmsprojects].[dbo].[booking].bookingnumber)     [fmsprojects].[dbo].[booking]    inner join [fmsprojects].[dbo].[container] on [fmsprojects].[dbo].[booking].[bookingnumber] = [fmsprojects].[dbo].[container].[bookingnumber]    inner join [fmsprojects].[dbo].[file] on [fmsprojects].[dbo].[container].filenumber = [fmsprojects].[dbo].[file].filenumber    [fmsprojects].[dbo].[booking].relationcode = 'ship02' , [fmsprojects].[dbo].[file].eta between '2000-10-27' , '2016-10-28' ) tmp;

-

Comments

Post a Comment

Popular posts from this blog

python - How to insert QWidgets in the middle of a Layout? -

Image
i'm using qt framework build graphical user interface. use qgridlayout position qwidgets neatly. gui looks this: my application regularly adds new widgets gui @ runtime. these new widgets not added @ end of qlayout, somewhere in middle. the procedure bit cumbersome. applied on figure above, need take out widg_c , widg_d , ... qgridlayout. next, add widg_x and widg_y , , put other widgets again. how remove widgets qgridlayout: for in reversed(range(mygridlayout.count())): self.itemat(i).widget().setparent(none) ### as long you're dealing small amount of widgets, procedure not disaster. in application display lot of small widgets - perhaps 50 or more! application freezes second while procedure ongoing, annoying user. there way insert widgets somewhere in qlayout, without need take out other widgets? edit: apparently solution qvboxlayout simple. use function insertwidget(..) instead of addwidget(..) . docs can found link: http://doc.qt.io/qt-5/qboxlayou
Read more

python - serve multiple gunicorn django instances under nginx ubuntu -

i need serve 2 webs apps (django) on gunicorn under different domain names using nginx on ubuntu. started using tutorial: https://www.digitalocean.com/community/tutorials/how-to-set-up-django-with-postgres-nginx-and-gunicorn-on-ubuntu-16-04 it worked fine 1 using that. tried same thing second gives me 502 gateway second domain. tried following tutorial: http://michal.karzynski.pl/blog/2013/10/29/serving-multiple-django-applications-with-nginx-gunicorn-supervisor/ i'm @ part run gunicorn start script: sudo bin/gunicorn_start i response: starting webuildblack root traceback (most recent call last): file "/home/devin/webuildblack/bin/gunicorn", line 7, in <module> gunicorn.app.wsgiapp import run importerror: no module named 'gunicorn.app'; 'gunicorn' not package you have named program gunicorn.py gunicorn -package. rename file , remove gunicorn.pyc file.
Read more

module - Prestashop displayPaymentReturn hook url -

i new prestashop developer , trying create paymentmodule. have got show payment method can not proceed purchase because not know hot works. does know should redirect run hooddisplaypaymentreturn method? i happy if explain me complete navigation map make purchase. anyway, can find relation between hooks , pages? when have new module payment rely on simplest provided prestashop: bankwire. inside can find 3 hooks. hookpayment: public function hookpayment($params) { if (!$this->active) return; if (!$this->checkcurrency($params['cart'])) return; $this->smarty->assign(array( 'this_path' => $this->_path, 'this_path_bw' => $this->_path, 'this_path_ssl' => tools::getshopdomainssl(true, true).__ps_base_uri__.'modules/'.$this->name.'/' )); return $this->display(__file__, 'payment.tpl'); } hookdisplaypaymenteu: public fun
Read more