python - Pointwise Mutual Information from scratch -


i want write own pmi (python) code without relying on nltk.

i know have use formula log(p(x , y)/p(x)p(y))

suppose have corpus c contains n words , looking bigrams. right in thinking that:

p(x) = (the number of times first word occurs) / (n)  p(y) = (the number of times second word occurs) / (n)  p(x , y) = (the number of times first word , the second  word occur bigram) / (the total number of bigrams)

for example, if had sentence "the fox jumped on fence".

the pmi(fox, jumped) worked out using:

p(x) = 1/6

p(y) = 1/6

p(x , y) = 1/5 (as there 5 distinct bigrams pairs , 1 of them "the fox")

any advice appreciated.


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