java - Placement of Math.toRadians for solving quadratic and cubic equations -

i writing program solves either quadratic or cubic equations. thing don't know if placing math.toradians correctly.

the code following:

public double[] getraices(double a,double b, double c, double d) throws complexexception {     if (a==0){         double discriminante=math.pow(c,2)+((-4)*b*d);         if(discriminante>=0){             this.raices[0]=(c*(-1)+math.sqrt(discriminante))/(2*b);             this.raices[1]=(c*(-1)-math.sqrt(discriminante))/(2*b);         }else{             throw new complexexception("no hay solucion real");         }      } else{         double f=((3*c/a)-(math.pow(b,2)/math.pow(a,2)))/3;         double g=((2*math.pow(b,3)/math.pow(a,3))-(9*b*c/math.pow(a,2))+(27*d/a))/27;         double h=(math.pow(g,2)/4)+(math.pow(f,3)/27);         if(f+g+h==0){             raices [0]=math.cbrt(d/a)*(-1);             raices [1]=math.cbrt(d/a)*(-1);             raices [2]=math.cbrt(d/a)*(-1);         }else{             if(h<=0){                 double i=math.sqrt((math.pow(g,2)/4)-h);                 double j=math.cbrt(i);                 double k=math.acos(math.toradians(-1*(g/2*i)));                 system.out.println(" "+k+" ");                 double l=j*(0-1);                 double m=math.toradians(math.cos(math.toradians(k/3)));                 system.out.println(" "+m+" ");                 double n=math.sqrt(3)*math.sin(math.toradians(k/3));                 system.out.println(" "+n+" ");                 double p=(b/(3*a)*(0-1));                 raices [0]=2*j*math.cos(math.toradians(k/3))-(b/(3*a));                 raices [1]=(l*(m+n))+p;                 raices [2]=(l*(m-n))+p;             }else{                 double r=((0-1)*(g/2))+math.sqrt(h);                 double s=math.cbrt(r);                 double t=((0-1)*(g/2))-math.sqrt(h);                 double u=math.cbrt(t);                 throw new complexexception("2 de las raices son imaginarias pero una raiz es real: "+math.floor(raices [0]=(s+u)-(b/(3*a))));             }         }     }     return raices; } 

but problem in if (h<=0).

i tested code against web page , found several errors. first g /2i, wrote g/2*i instead of g/2/i or (g/(2*i). , several math.toradians not necessary (webpage said calculations in radians, no need convert).

i added println following formula :

package test;  public class cubic {     private double[] raices = new double[3];      public static void main(string[] args) throws complexexception {         double[] raices = new cubic().getraices(2, -4, -22, 24);         system.out.println(raices[0] + "," + raices[1] + "," + raices[2]);     }      public double[] getraices(double a, double b, double c, double d) throws complexexception {         if (a == 0) {             double discriminante = math.pow(c, 2) + ((-4) * b * d);             if (discriminante >= 0) {                 this.raices[0] = (c * (-1) + math.sqrt(discriminante)) / (2 * b);                 this.raices[1] = (c * (-1) - math.sqrt(discriminante)) / (2 * b);             } else {                 throw new complexexception("no hay solucion real");             }          } else {             double f = ((3 * c / a) - (math.pow(b, 2) / math.pow(a, 2))) / 3;             system.out.println("f=" + f);             double g = ((2 * math.pow(b, 3) / math.pow(a, 3)) - (9 * b * c / math.pow(a, 2)) + (27 * d / a)) / 27;             system.out.println("g=" + g);             double h = (math.pow(g, 2) / 4) + (math.pow(f, 3) / 27);             system.out.println("h=" + h);             if (f + g + h == 0) {                 raices[0] = math.cbrt(d / a) * (-1);                 raices[1] = math.cbrt(d / a) * (-1);                 raices[2] = math.cbrt(d / a) * (-1);             } else {                 if (h <= 0) {                     double = math.sqrt((math.pow(g, 2) / 4) - h);                     double j = math.cbrt(i);                     double k = math.acos(-1 * (g / 2 / i));                     system.out.println("k=" + k + " ");                     double l = j * (0 - 1);                     system.out.println("l=" + l + " ");                     double m = math.cos(k / 3);                     system.out.println("m= " + m + " ");                     double n = math.sqrt(3) * math.sin(k / 3);                     system.out.println("n= " + n + " ");                     double p = (b / (3 * a) * (0 - 1));                     system.out.println("p= " + p + " ");                     raices[0] = 2 * j * math.cos(k / 3) - (b / (3 * a));                     raices[1] = (l * (m + n)) + p;                     raices[2] = (l * (m - n)) + p;                 } else {                     double r = ((0 - 1) * (g / 2)) + math.sqrt(h);                     double s = math.cbrt(r);                     double t = ((0 - 1) * (g / 2)) - math.sqrt(h);                     double u = math.cbrt(t);                     throw new complexexception(                             "2 de las raices son imaginarias pero una raiz es real: " + math.floor(raices[0] = (s + u) - (b / (3 * a))));                 }             }         }         return raices;     } }